Quantrex Academy · Free NEET PYQ solutions
NEET Physics Electrostatics 2024 NEET 2024

NEET Physics Question (2024) — Solution

Question

Given below are two statements: one is labelled as Assertion A and the other is labelled as Reason R . Assertion A: The potential (V) at any axial point, at 2 m distance (r) from the centre of the dipole of dipole moment vector P of magnitude, 4 10^ -6 C m , is 9 10^3 ~V . (Take 1 4 _0 =9 10^9 SI units) Reason R : V= 2 P 4 _0 r^2 , where r is the distance of any axial point, situated at 2 m from the centre of the dipole. In the light of the above statements, choose the correct answer from the options given below:

Options

  1. A. Both A and R are true and R is NOT the correct explanation of A .
  2. B. A is true but R is false.
  3. C. A is false but R is true.
  4. D. Both A and R are true and R is the correct explanation of A.

Answer

B. A is true but R is false.

Step-by-step solution

The potential V at any point, at distance r from centre of dipole = K P r^2 At axial point where =0^ , V= K P r^2 = 9 10^9 4 10^ -6 2^2 =9 10^3 ~V At axial point where =180^ , V= -K P r^2 =-9 10^3 ~V

Practice more on Quantrex App →

Related: Physics — Electrostatics · All PYQ Banks