The pitch of an error free screw gauge is 1 mm and there are 100 divisions on the circular scale. While measuring the diameter of a thick wire, the pitch scale reads 1 mm and 63^ rd division on the circular scale coincides with the reference line. The diameter of the wire is:

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Correct answer: B. 0.163 cm

Least count of screw gauge = Pitch No. of divisions on circular scale Least count = 1 100 =0.01 ~mm Final reading = MSR + CSR L.C. =1 ~mm +(63)(0.01) mm =1.63 ~mm =0.163 ~cm

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