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NEET Physics Question (2025) — Solution

Question

Consider the diameter of a spherical object being measured with the help of a Vernier callipers. Suppose its 10 Vernier Scale Divisions (V.S.D.) are equal to its 9 Main Scale Divisions (M.S.D.) The least division in the M.S. is 0.1 cm and the zero of V.S. is at x =0.1 ~cm when the jaws of Vernier callipers are closed. If the main scale reading for the diameter is M =5 ~cm and the number of coinciding vernier division is 8 , the measured diameter after zero error correction, is

Options

  1. A. 5.18 cm
  2. B. 5.08 cm
  3. C. 4.98 cm
  4. D. 5.00 cm

Answer

C. 4.98 cm

Step-by-step solution

aligned & 10 V.S.D. =9 M.S.D. \\ & 1 M.S.D. =0.1 ~cm (Given) \\ & 1 V.S.D. =0.9 M.S.D. \\ & 1 V.S.D. =0.9 0.1 ~cm \\ & V.S.D. =0.09 ~cm \\ & L.C. =1 M.S.D. -1 V.S.D. \\ & =(0.1-0.09) cm \\ & =0.01 ~cm \\ & Reading =5.08 ~cm \\ & Positive zero error =0.1 ~cm (Given) \\ & Final Corrected reading =(5.08-0.1) cm \\ & =4.98 ~cm aligned

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