Question
In a vernier callipers, 20 VSD coincide with 16 MSD (each division of length 1 mm). The least count of the vernier callipers is :
NEET
Physics
Experimental Physics
2026
NEET 2026 (Cancelled)
NEET Physics Question (2026) — Solution
Options
- A. 0.2 cm
- B. 0.01 cm
- C. 0.02 cm
- D. 0.1 cm
Answer
C. 0.02 cm
Step-by-step solution
Given 20 VSD = 16 MSD. 1 VSD = 16 20 MSD = 0.8 MSD. Least count is given by 1 MSD - 1 VSD. Least count = 1 MSD - 0.8 MSD = 0.2 MSD. Since 1 MSD = 1 mm, we get Least count = 0.2 mm. Converting to cm, Least count = 0.02 cm. Answer: 0.02 cm
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