Question
The magnitude and direction of the acceleration produced in a body of mass 5 kg when two mutually perpendicular forces 8 N and 6 N act on it, are respectively :
NEET
Physics
Laws of Motion
2026
NEET 2026 (Cancelled)
NEET Physics Question (2026) — Solution
Options
- A. 20 m s^ -2 ; ^ -1 (4/3) with 8 N force
- B. 2 m s^ -2 ; ^ -1 (3/4) with 6 N force
- C. 2 m s^ -2 ; ^ -1 (4/3) with 8 N force
- D. 2 m s^ -2 ; ^ -1 (3/4) with 8 N force
Answer
D. 2 m s^ -2 ; ^ -1 (3/4) with 8 N force
Step-by-step solution
Given forces are F_1 = 8 N and F_2 = 6 N acting perpendicular to each other. The magnitude of the net force is F = F_1^2 + F_2^2 = 8^2 + 6^2 = 10 N. The magnitude of acceleration is a = F m = 10 5 = 2 m s^ -2 . Let be the angle made by the net force with the 8 N force. = F_2 F_1 = 6 8 = 3 4 = ^ -1 ( 3 4 ) with the 8 N force. Answer: 2 m s^ -2 ; ^ -1 (3/4) with 8 N force
Related: Physics — Laws of Motion · All PYQ Banks