A tightly wound 100 turns coil of radius 10 cm carries a current of 7 A . The magnitude of the magnetic field at the centre of the coil is (Take permeability of free space as 4 10^ -7 SI units):

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Correct answer: B. 4.4 mT

The magnitude of magnetic field due to circular coil of N turns is given by aligned & B_C= _0 i N 2 R \ & = 4 10^ -7 7 100 2 0.1 \ & =4.4 10^ -3 ~T \ & =4.4 mT aligned

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