Savitha, a XI standard student, while conducting an experiment to determine the effective length of a simple pendulum L, notes down the data of time taken to complete 30 oscillations as 60 s and hence calculates the length of the simple pendulum as : (Take ^2 = 9.8, and g = 9.8 m/s^2)
D. 1 m
Time period T = 60 30 = 2 s. The formula for the time period of a simple pendulum is T = 2 L g . Squaring both sides, we get T^2 = 4 ^2 L g . Substituting the given values T = 2 s, ^2 = 9.8, and g = 9.8 m/s^2: (2)^2 = 4 9.8 L 9.8 4 = 4L L = 1 m. Answer: 1 m
Related: Physics — Oscillations · All PYQ Banks