The moment of inertia of a thin rod about an axis passing through its mid point and perpendicular to the rod is 2400 ~g ~cm ^2. The length of the 400 g rod is nearly:

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Correct answer: D. 8.5 cm

Moment of inertia of rod =I= m ^2 12 aligned & 2400=400 ^2 12 \ & 72= ^2 \ & = 72 =8.48 ~cm 8.5 ~cm aligned

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