NEET Physics Question (2026) — Solution

Step-by-step solution

The dimensional formula for the Stefan-Boltzmann constant _s is obtained from the relation E = _s A t T^4, where E is energy, A is area, t is time, and T is temperature: [ _s] = [ M L ^2 T ^ -2 ] [ L ^2][ T ][ K ^4] = [ M T ^ -3 K ^ -4 ] The dimensional formula for the Boltzmann constant k_B is obtained from E = k_B T: [k_B] = [ M L ^2 T ^ -2 ] [ K ] = [ M L ^2 T ^ -2 K ^ -1 ] The dimensional formula for Wien's displacement constant b is obtained from _ max T = b: [b] = [ L ][ K ] = [ L K ] Now, substituting these dimensions into the given expression _s k_B^ -1 b: [ _s k_B^ -1 b] = [ _s][b] [k_B] [ _s k_B^ -1 b] = [ M T ^ -3 K ^ -4 ][ L K ] [ M L ^2 T ^ -2 K ^ -1 ] [ _s k_B^ -1 b] = [ M L T ^ -3 K ^ -3 ] [ M L ^2 T ^ -2 K ^ -1 ] [ _s k_B^ -1 b] = [ L ^ -1 T ^ -1 K ^ -2 ] Answer: [ L ^ -1 T ^ -1 K ^ -2 ]