Question
Two slits in Young's double slit experiment are 1.5 mm apart and the screen is placed at a distance of 1 m from the slits. If the wavelength of light used is 600 10^ -9 ~m then the fringe separation is
NEET
Physics
Wave Optics
2024
NEET 2024 (Re-NEET)
NEET Physics Question (2024) — Solution
Options
- A. 4 10^ -5 ~m
- B. 9 10^ -8 ~m
- C. 4 10^ -7 ~m
- D. 4 10^ -4 ~m
Answer
D. 4 10^ -4 ~m
Step-by-step solution
Fringe width = Fringe separation ( )= D d = 600 10^ -9 1 1.5 10^ -3 = 6 10^ -7 1.5 10^ -3 =4 10^ -4 ~m
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