The kinetic energies of two similar cars A and B are 100 J and 225 J respectively. On applying breaks, car A stops after 1000 m and car B stops after 1500 m . If F _ A and F _ B are the forces applied by the breaks on cars A and B , respectively, then the ratio F _ A / F _ B is :

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Correct answer: B. 2 3

aligned & W.D. = KE \ aligned F . S = KE aligned & ( K E)_A ( K E)_B = - F _A S_A - F _ B ~S _ B \ & -100 -225 = - F _ A (1000) - F _ B (1500) \ & F _ A ~F _ B = 2 3 aligned

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