Each side of a metallic cube of mass 5.580 kg is measured to be 9.0 cm. Keeping the significant figures in view, the density of the material of the cube can be best expressed as X 10³ kg m ⁻³ , where the value of X is :

Step-by-step solution

Mass of the metallic cube, m = 5.580 kg (4 significant figures) Side length of the cube, a = 9.0 cm = 9.0 10⁻² m (2 significant figures) Volume of the cube, V = a^3 = (9.0 10⁻²)^3 = 729 10⁻⁶ m ^3 Density of the material, = m V = 5.580 729 10⁻⁶ = 7.6543... 10^3 kg m ⁻³ In multiplication or division, the final result should retain as many significant figures as are present in the original number with the least significant figures. Here, the side length ( 9.0 cm) has the least number of significant figures, which is 2