If the mass of the object is measured as m = (7 0.14) kg and the density is measured as = (5 0.25) kg/m^3 respectively. The percentage error in the measurement of volume is

Correct answer: C. 7\% Volume is given by the relation V = (m)/( ) The maximum percentage error in volume is (Δ V)/(V) × 100 = ( (Δ m)/(m) + (Δ )/( ) ) × 100 Substituting the given values: (Δ V)/(V) × 100 = ( (0.14)/(7) + (0.25)/(5) ) × 100 (Δ V)/(V) × 100 = (0.02 + 0.05) × 100 (Δ V)/(V) × 100 = 0.07 × 100 = 7\% Answer: 7\%

MHT CET 202623 AprilMorning Shift

Exam: MHT CET
Year: 2026
Date: 23 April
Shift: Morning Shift
Subject: Physics
Chapter: Units and Dimensions

MHT CET 2026 · 23 April · Morning Shift · Physics · Units and Dimensions

If the mass of the object is measured as m = (7 0.14) kg and the...

If the mass of the object is measured as

m = (7 \mp 0.14)

kg and the density is measured as

\rho = (5 \mp 0.25)

kg/m^3 respectively. The percentage error in the measurement of volume is

Options

A $3\%$
B $5\%$
C $7\%$
D $9\%$

Correct answer

C. $7\%$

Step-by-step solution

Volume is given by the relation

V = \dfrac{m}{\rho}

The maximum percentage error in volume is

\dfrac{\Delta V}{V} \times 100 = \left( \dfrac{\Delta m}{m} + \dfrac{\Delta \rho}{\rho} \right) \times 100

Substituting the given values:

\dfrac{\Delta V}{V} \times 100 = \left( \dfrac{0.14}{7} + \dfrac{0.25}{5} \right) \times 100

\dfrac{\Delta V}{V} \times 100 = (0.02 + 0.05) \times 100

\dfrac{\Delta V}{V} \times 100 = 0.07 \times 100 = 7\%

Answer:

7\%

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