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NEET
Exam
NEET
Subject
Physics
Chapter
Motion in Two Dimensions

NEET · Physics · Motion in Two Dimensions

Three vectors → P , → Q and → R are shown in the figure. Let, S be...

Three vectors P→,Q→\overset{\to}{P}, \overset{\to}{Q} and R→\overset{\to}{R} are shown in the figure. Let, SS be any point on the vector R→\overset{\to}{R} . The distance between the points PP and SS is b∣R→∣b\left|\overset{\to}{R}\right|. The general relation among vectors P→,Q→\overset{\to}{P}, \overset{\to}{Q} and S→\overset{\to}{S} are
Three vectors → P , → Q and → R are shown in the figure. Let, S be any point on the vector → R . The distance between

Options

  1. AS→=(1−b)P→+b2Q→\overset{\to}{S} = \left(1 - b\right)\overset{\to}{P} + {b}^{2}\overset{\to}{Q}
  2. BS→=(B−1)P→+bQ→\overset{\to}{S} = \left(B - 1\right)\overset{\to}{P} + b\overset{\to}{Q}
  3. CS→=(1−b)P→+bQ→\overset{\to}{S} = \left(1 - b\right)\overset{\to}{P} + b\overset{\to}{Q}
  4. DS→=(1−b2)P→+bQ→\overset{\to}{S} = \left(1 - {b}^{2}\right)\overset{\to}{P} + b\overset{\to}{Q}

Correct answer

C. S→=(1−b)P→+bQ→\overset{\to}{S} = \left(1 - b\right)\overset{\to}{P} + b\overset{\to}{Q}

Step-by-step solution

Three vectors → P , → Q and → R are shown in the figure. Let, S be any point on the vector → R . The distance between

Let, vector from point PP to point SS be C→\overset{\to}{C}, 

⇒ \overset{\to}{C} = b\left|\overset{\to}{R}\right|\overset{^}{R} = b\left|\overset{\to}{R}\right|\left(\overset{\to}{R}\left|\overset{\to}{R}\right|\right) = b\overset{\to}{R} = b\left(\overset{\to}{Q} - \overset{\to}{P}\right)

From triangle rule of vector addition, 

P→+C→=S→\overset{\to}{P} + \overset{\to}{C} = \overset{\to}{S}

P→+b(Q→−P→)=S→\overset{\to}{P} + b\left(\overset{\to}{Q} - \overset{\to}{P}\right) = \overset{\to}{S}

⇒S→=(1−b)P→+bQ→⇒ \overset{\to}{S} = \left(1 - b\right)\overset{\to}{P} + b\overset{\to}{Q}

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