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NEET
Exam
NEET
Subject
Physics
Chapter
Motion in Two Dimensions

NEET · Physics · Motion in Two Dimensions

The position of a particle is given by r=3.0t i +2.0 t ^ 2 j +5.0 k...

The position of a particle is given by r=3.0ti^+2.0t2j^+5.0k^r=3.0t\hat{i}+2.0{{t}^{2}}\hat{j}+5.0\hat{k} where t is in seconds and the coefficients have the proper units for r to be in meters. Find v(t) and a(t) of the particle.

Options

  1. Aa(t)= 4.0j^ , v(t)= 3.0i^+3.0j^a\left( t \right)=~4.0\hat{j}~,~v\left( t \right)=~3.0\hat{i}+3.0\hat{j}
  2. Ba(t)= 5.0j^ , v(t)= 4.0i^+4.0j^a\left( t \right)=~5.0\hat{j}~,~v\left( t \right)=~4.0\hat{i}+4.0\hat{j}
  3. Ca(t)= 4.0j^ , v(t)= 3.0i^+4.0j^a\left( t \right)=~4.0\hat{j}~,~v\left( t \right)=~3.0\hat{i}+4.0\hat{j}
  4. Da(t)= 5.0j^ , v(t)= 3.0i^+4.0j^a\left( t \right)=~5.0\hat{j}~,~v\left( t \right)=~3.0\hat{i}+4.0\hat{j}

Correct answer

C. a(t)= 4.0j^ , v(t)= 3.0i^+4.0j^a\left( t \right)=~4.0\hat{j}~,~v\left( t \right)=~3.0\hat{i}+4.0\hat{j}

Step-by-step solution

Correct Option is : (C)
a(t)= 4.0j^ , v(t)= 3.0i^+4.0j^a\left( t \right)=~4.0\hat{j}~,~v\left( t \right)=~3.0\hat{i}+4.0\hat{j}
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