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NEET
Exam
NEET
Subject
Physics
Chapter
Motion in Two Dimensions

NEET · Physics · Motion in Two Dimensions

For any arbitrary motion in space, which of the following relation...

For any arbitrary motion in space, which of the following relation is true :

Options

  1. Avaverage= 12(v(t1)−v(t2)){{v}_{average}}=~\frac{1}{2}\left( v\left( {{t}_{1}} \right)-v\left( {{t}_{2}} \right) \right)
  2. Bvaverage= r(t2)−r(t1)(t2−t1){{v}_{average}}=~\frac{r\left( {{t}_{2}} \right)-r\left( {{t}_{1}} \right)}{\left( {{t}_{2}}-{{t}_{1}} \right)}
  3. Cv(t)=v0+atv\left( t \right)={{v}_{0}}+at
  4. Dr(t)=r0+v0t+12atr\left( t \right)={{r}_{0}}+{{v}_{0}}t+\frac{1}{2}at

Correct answer

B. vaverage= r(t2)−r(t1)(t2−t1){{v}_{average}}=~\frac{r\left( {{t}_{2}} \right)-r\left( {{t}_{1}} \right)}{\left( {{t}_{2}}-{{t}_{1}} \right)}

Step-by-step solution

Correct Option is : (B)
vaverage= r(t2)−r(t1)(t2−t1){{v}_{average}}=~\frac{r\left( {{t}_{2}} \right)-r\left( {{t}_{1}} \right)}{\left( {{t}_{2}}-{{t}_{1}} \right)}
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