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NEET
Exam
NEET
Subject
Physics
Chapter
Motion in Two Dimensions

NEET · Physics · Motion in Two Dimensions

A particle is projected in air at an angle β to a surface which...

A particle is projected in air at an angle β to a surface which itself is inclined at an angle α to the horizontal Find an expression of range on the plane surface

Options

  1. AL=2vo2sinβcos⁡(α+β)gcos2βL=\frac{2{{v}_{o}}^{2}sin\beta \cos \left( \alpha +\beta \right)}{gco{{s}^{2}}\beta }
  2. BL=2vo2sinβcos⁡2βgcos2αL=\frac{2{{v}_{o}}^{2}sin\beta \cos 2\beta }{gco{{s}^{2}}\alpha }
  3. CL=2vo2sinβcos⁡(α+β)gcos2αL=\frac{2{{v}_{o}}^{2}sin\beta \cos \left( \alpha +\beta \right)}{gco{{s}^{2}}\alpha }
  4. DL=2vo2sinβcos⁡2αgcos2βL=\frac{2{{v}_{o}}^{2}sin\beta \cos 2\alpha }{gco{{s}^{2}}\beta }

Correct answer

C. L=2vo2sinβcos⁡(α+β)gcos2αL=\frac{2{{v}_{o}}^{2}sin\beta \cos \left( \alpha +\beta \right)}{gco{{s}^{2}}\alpha }

Step-by-step solution

Correct Option is : (C)
L=2vo2sinβcos⁡(α+β)gcos2αL=\frac{2{{v}_{o}}^{2}sin\beta \cos \left( \alpha +\beta \right)}{gco{{s}^{2}}\alpha }
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