Two projectiles are fired from the ground with the same initial speed u . One is fired at an angle with the horizontal, and the other is fired at an angle (90^ - ) with the horizontal. The sum of their maximum heights is:

Step-by-step solution

The maximum height of a projectile is given by H = u^2 ^2 2g . For the first projectile fired at an angle : H₁ = u^2 ^2 2g For the second projectile fired at an angle (90^ - ) : H₂ = u^2 ^2(90^ - ) 2g = u^2 ^2 2g The sum of their maximum heights is: H₁ + H₂ = u^2 ^2 2g + u^2 ^2 2g H₁ + H₂ = u^2 2g ( ^2 + ^2 ) Using the trigonometric identity ^2 + ^2 = 1 , we get: H₁ + H₂ = u^2 2g Answer: u^2 2g