A ball is thrown such that its horizontal range is exactly 4 3 times its maximum height. The angle of projection with the horizontal is:

Step-by-step solution

The horizontal range R and maximum height H of a projectile are given by: R = u^2 (2 ) g = u^2 (2 ) g H = u^2 ^2 2g According to the given condition, R = 4 3 H . Substituting the formulas: u^2 (2 ) g = 4 3 ( u^2 ^2 2g ) Cancelling u^2 g from both sides: 2 = 2 3 ^2 Assuming 0 , we can divide both sides by 2 : 1 = 3 = 1 3 = 30^ Answer: 30^