NEET
- Exam
- NEET
- Subject
- Physics
- Chapter
- Motion in Two Dimensions
NEET · Physics · Motion in Two Dimensions
A particle is executing uniform circular motion. Match the...
A particle is executing uniform circular motion. Match the kinematic quantities in List-I with their corresponding properties in List-II.
Choose the correct answer from the options given below:
| List-I | List-II |
|---|---|
| A. Velocity | I. Constant scalar |
| B. Speed | II. Constant vector |
| C. Tangential acceleration | III. Changing vector |
| D. Angular velocity | IV. Zero vector |
Choose the correct answer from the options given below:
Options
- AA-II, B-I, C-IV, D-III
- BA-III, B-I, C-IV, D-II
- CA-III, B-II, C-I, D-IV
- DA-III, B-I, C-II, D-IV
Correct answer
B. A-III, B-I, C-IV, D-II
Step-by-step solution
In uniform circular motion, the particle moves with a constant speed. Thus, speed is a constant scalar.
The direction of motion changes continuously along the circular path, meaning the velocity vector changes its direction at every point. Hence, velocity is a changing vector.
Tangential acceleration is the rate of change of speed. Since speed is constant, the tangential acceleration is zero, making it a zero vector.
Angular velocity is given by the right-hand thumb rule and points along the axis of rotation. In uniform circular motion, both its magnitude and direction remain constant. Thus, angular velocity is a constant vector.
Therefore, the correct matching is A-III, B-I, C-IV, D-II.
Answer: A-III, B-I, C-IV, D-II
The direction of motion changes continuously along the circular path, meaning the velocity vector changes its direction at every point. Hence, velocity is a changing vector.
Tangential acceleration is the rate of change of speed. Since speed is constant, the tangential acceleration is zero, making it a zero vector.
Angular velocity is given by the right-hand thumb rule and points along the axis of rotation. In uniform circular motion, both its magnitude and direction remain constant. Thus, angular velocity is a constant vector.
Therefore, the correct matching is A-III, B-I, C-IV, D-II.
Answer: A-III, B-I, C-IV, D-II