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JIPMER 2018
Exam
JIPMER
Year
2018
Subject
Physics
Chapter
Motion in Two Dimensions

JIPMER 2018 · Physics · Motion in Two Dimensions

What is the range of a projectile thrown with velocity 98 ~m / s...

What is the range of a projectile thrown with velocity 98 m/s98 \mathrm{~m} / \mathrm{s} with angle 30∘30^{\circ} from horizontal ?

Options

  1. A4903 m490 \sqrt{3} \mathrm{~m}
  2. B2453 m245 \sqrt{3} \mathrm{~m}
  3. C9803 m980 \sqrt{3} \mathrm{~m}
  4. D100m100 m

Correct answer

A. 4903 m490 \sqrt{3} \mathrm{~m}

Step-by-step solution

Given, U=98 m/s,θ=30∘\mathrm{U}=98 \mathrm{~m} / \mathrm{s}, \theta=30^{\circ} ∵\because Range of a projectile, R=U2sin⁡(2θ)g\mathrm{R}=\frac{\mathrm{U}^2 \sin (2 \theta)}{\mathrm{g}} =98×98×sin⁡60∘9.8=4903 m=\frac{98 \times 98 \times \sin 60^{\circ}}{9.8}=490 \sqrt{3} \mathrm{~m}
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