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NEET2004PhysicsMotion in Two DimensionsActual

A stone is thrown with an initial speed of 4.9 ~m / s from a bridge in vertically upward direction. It falls down in water after 2 sec . The height of bridge is

Options

  1. A24.7 m
  2. B19.8 m
  3. C9.8 m
  4. D4.9 m

Correct answer

C. 9.8 m

Step-by-step solution

Here: Initial velocity u=-4.9 ~m / s (- ve is due to vertically upward motion) Total time t=2 sec The height of the bridge is given by s=u t+ 1 2 g t^2 aligned & =-4.9 2+ 1 2 9.8 (2)^2 & =-9.8+19.6=9.8 ~m aligned

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