NEET
- Exam
- NEET
- Subject
- Physics
- Chapter
- Laws of Motion
NEET · Physics · Laws of Motion
Assertion : A block of weight 10 N is pushed against a vertical...
Assertion : A block of weight 10 N is pushed against a vertical wall by a force of 15 N. The coefficient of friction between the wall and the block is 0.6. Then, the magnitude of maximum frictional force is 9 N.
Reason : For given system block will remain stationary.
Options
- AIf both Assertion and Reason are correct and Reason is the correct explanation of Assertion
- BIf both Assertion and Reason are true but Reason is not the correct explanation of Assertion
- CIf Assertion is true but Reason is false
- DIf Assertion is false but Reason is true
Correct answer
C. If Assertion is true but Reason is false
Step-by-step solution
- Normal reaction from the wall equals the horizontal push: (), so maximum static friction f_max (=\mu 0.6 15=9 ) (Assertion true).
- To remain at rest, friction must balance weight 10 N , but available friction is only 9 N , so the block slides down; the "block will remain stationary" statement is false (Reason false).