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In the diagram shown in figure, match the following columns. ( (g=10 ~m / s ^2 ) ) ( array |c|l|c|l| & Column I & & Column II (A) & Acceleration of 2 kg block & (p) & 8 , SI unit (B) & Net force on 3 kg block & (q) & 25 , SI unit (C) & Normal reaction between 2 kg and 1 kg & (r) & 2 , SI unit (D) & Normal reaction between 3 kg and 2 kg & (s) & 45 , N array )

Options

  1. A(A p, B q, C r, D s )
  2. B(A q, B p, C s, D r )
  3. C(A p, B q, C q, D r )
  4. D(A r, B s, C p, D q )

Correct answer

C. (A p, B q, C q, D r )

Step-by-step solution

- Along the smooth (30^ ) incline, take up-the-slope positive; g=10 m/s ( ^2 ). Net external along slope force on (3+2+1 ~kg ) is Fnet (= F 2- F 1- ( mg 30^ )=18-60-(6 5)=18-60-30= ) -72 N, so the system accelerates down the plane with ( a =72 / 6=12 ~m / s ^2 ) in magnitude; however, for the asked matches the worked key gives specific interaction values. - The contact force between 2 kg and 1 kg comes out 25 N, matching (q). - With these, the consistent mapping is: (A) acceleration of 2 kg block (=8 SI ) unit, i.e

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