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NEETPhysicsLaws of Motion

What is the force acting on a particle of mass m described by the equation y = (1/2)ut^2 + (1/2)gt^2?

Options

  1. AF = 0
  2. BF = mg
  3. CF = mgt
  4. DF = mu

Correct answer

B. F = mg

Step-by-step solution

Correct Option is : (B) F = mg

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