Match the physical situations involving a block of mass m on a smooth inclined plane of angle (List-I) with their corresponding expressions (List-II). List-I List-II A. Acceleration of a block sliding freely down the incline I. mg B. Normal reaction on a block sliding freely down the incline II. g C. Minimum horizontal force required to keep the block stationary III. mg D. Normal reaction on a block kept stationary b

Step-by-step solution

A. For a block sliding freely down a smooth incline, the only force along the incline is mg . Acceleration a = mg m = g . B. The force perpendicular to the incline is balanced. Normal reaction N = mg . C. To keep the block stationary with a horizontal force F , the component of F up the incline must balance the weight component down the incline: F = mg F = mg . D. The normal reaction in this case balances both the perpendicular component of weight and the perpendicular component of the horizontal force: N = mg + F