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NEET2009PhysicsLaws of MotionActual

Three equal weights of 3 ~kg each are hanging on a string passing over a frictionless pulley as shown in figure. The tension in the string between masses II and III will be (Take g=10 ~m / sec ^2 )

Options

  1. A5 ~N
  2. B6 ~N
  3. C10 ~N
  4. D20 ~N

Correct answer

D. 20 ~N

Step-by-step solution

Three equal weights of 3 ~kg each are hanging on a string passing over a pulley as shown in figure. If a is the common acceleration. T-3 g=3 a (For mass I) 3 g+T₁-T=3 a (For mass II) 3 g-T₁=3 a (For mass III) Adding, above three equations aligned & 3 g=9 a, a=g / 3 & T₁=3 g-3 a=3 g-g=2 g=20 ~N aligned

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