NEET2018PhysicsLaws of MotionActual
A mass M is hung with a light inextensible string as shown in the figure. Find the tension of the horizontal string.
Options
- A2 Mg
- B3 M g
- C2 Mg
- D3 Mg
Correct answer
B. 3 M g
Step-by-step solution
As there is a load at P , so tension in AP and PB will be different. Let these be T ₁ and T ₂ respectively. For vertical equilibrium of P , T ₂ 60^ = Mg i.e., T ₂=2 Mg ...(i) And for horizontal equilibrium of P , T ₁= T ₂ 60^ = T ₂( 3 / 2) ...(i) Substituting the value of T ₂ from Eq. (i), T ₁=(2 Mg ) ( 3 / 2)= 3 Mg