NEET2018PhysicsLaws of MotionActual
A ball of 0.5 kg collided with wall at 30^ and bounced back elastically. The speed of ball was 12 ~m / s . The contact remained for 1 s . What is the force applied by wall on ball?
Options
- A12 3 N
- B3 N
- C6 3 N
- D3 3 N
Correct answer
C. 6 3 N
Step-by-step solution
Given, m =0.5 ~kg , v =12 ~m / s , t =1 ~s , =30^ Force applied by wall on ball, F = p t or F = ( p _ f )_ H - ( p _ i )_ H t In this elastic collision, final and initial velocity will be same but direction will changed. Horizontal component, ( p _ f )_ H = mv and ( p _ i )_ H =- mv aligned & F = mv -(- mV ) t = 2 mV t & = 2 0.5 12 30^ 1 =6 3 ~N & aligned