Two masses 10 kg and 20 kg respectively are connected by a massless spring as shown in figure. A force of 200 N acts on the 20 kg mass. At the instant shown is figure the 10 kg mass has acceleration of 12 ~m / s ^2 . The value of acceleration of 20 kg mass is

Step-by-step solution

Equation of motion of m₁=10 ~kg mass is F₁=m₁ a₁=10 12=120 ~N Force on 10 kg -mass is 120 N to the right. As action and reaction are equal and opposite, the reactions force F -on 20 kg mass F=120 ~N to the left. Equation of motion of mass m₂=20 ~kg is aligned 200-F & =20 a₂ 200-120 & =20 a₂ 20 a₂ & =80 a₂= 80 20 & =4 ~m / s ^2 aligned