A body is moving along a rough horizontal surface with an initial velocity of 10 ~ms ⁻¹ . If the body comes to rest after travelling a distance of 12 m , then the coefficient of sliding friction will be

Step-by-step solution

Given, u=10 ~ms ⁻¹, s=12 ~m , v=0 By third equation of motion, aligned v^2 & =u^2-2 a s 0 & =(10)^2-2 a 12 24 a & =100 a & =4.17 ~ms ⁻² aligned Coefficient of sliding friction is given by = a g = 4.17 10 =0.41