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NEET
Exam
NEET
Subject
Physics
Chapter
Center of Mass, Momentum and Collision

NEET · Physics · Center of Mass, Momentum and Collision

Match the following columns with respective positions of centre of...

Match the following columns with respective positions of centre of mass - (
Column - IColumn - II
(A)uniform rod length =R(P)x=\frac{3 R}{8}
(B)uniformthinsemicircular</td></tr><tr><td>ringofradiusR\begin{array}{l} uniform thin semicircular</td></tr><tr><td>ring of radius R \end{array}(Q)x=\frac{R}{2}
(C)unifiormsemicurcula</td></tr><tr><td>discofradiusR\begin{array}{l} unifiorm semicurcula</td></tr><tr><td>disc of radius R \end{array}(R)x=\frac{4 R}{3 \pi}
(D)uniformsolidhemisphere</td></tr><tr><td>ofradiusR\begin{array}{l} uniform solid hemisphere</td></tr><tr><td>of radius R \end{array}(S)x=\frac{2 R}{\pi}
)

Options

  1. AA:P,B:R,C:Q,D:SA: P, B: R, C: Q, D: S
  2. BA:Q,B:P,C:R,D:SA: Q, B: P, C: R, D: S
  3. CA:Q,B:S,C:R,D:PA: Q, B: S, C: R, D: P
  4. DA:S,B:P,C:Q,D:RA:S, B:P, C:Q, D:R

Correct answer

C. A:Q,B:S,C:R,D:PA: Q, B: S, C: R, D: P

Step-by-step solution

(A) Uniform rod of length RR - For a uniform rod, the COM lies exactly at the midpoint. So, (x=R2\frac{R}{2}). That matches (Q). (B) Uniform thin semicircular ring of radius R - Standard result: COM of a semicircular ring lies at a distance (2Rπ\frac{2 R}{\pi}) from the center, along symmetry axis. So, (x=2Rπ\frac{2 R}{\pi}). That matches (S). (C) Uniform semicircular disc of radius R - Standard result: COM of a semicircular lamina is at a distance (4R3π\frac{4 R}{3 \pi}) from the center along symmetry axis. So, (x=4R3π\frac{4 R}{3 \pi}). That matches (R). (D) Uniform solid hemisphere of radius R - Standard result: COM of a solid hemisphere is at a distance (3R8\frac{3 R}{8}) from the flat face (base). So, (x=3R8\frac{3 R}{8}). That matches (P).
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