NEETPhysicsCenter of Mass, Momentum and Collision
Particle of mass m, kinetic energy K and momentum P collides head on elastically with another particle of mass 2 m at rest. After collision: ( array |l|l|l|c| & Column I & & Column II (A) & Momentum of I ^ st particle & (P) & 4 3 P (B) & Momentum of II ^ rd particle & (Q) & K 9 (C) & KE ^ of I ^ sd particle & (R) & 8 ~K 9 (D) & KE ^ of II ^ rd particle & (S) & - P 3 array )
Options
- A( A S ; B P , C Q , D R )
- B( A P ; B S , C Q , D R )
- C( A P ; B S , C R , D Q )
- D( A S ; B P , C R , D Q )
Correct answer
A. ( A S ; B P , C Q , D R )
Step-by-step solution
(v₁ ~ &~ v₂ ) are velocities after collision Conservation of linear momentum ( gathered mu = mv ₁+2 mv ₂ u = v ₁+ v ₂ (1) e =1= v ₂- v ₁ u u = v ₂- v ₁ (2) gathered ) From (1) & (2) (v₂= 2 u 3 ; v₁=- u 3 ) Momentum of (1^ t ) particle (=- mu 3 =- P 3 ) Momentum of (2^ nd ) particle (=+2 ~m ( 2 u 3 )= 4 P 3 ) K.E. of (1^a ) particle (= 1 2 ~m ( u 3 )^2= K 9 ) K.E. of (2^ ) particle (= 1 2 2 ~m ( 2 u 3 )^2= 8 ~K 9 )