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NEET
Exam
NEET
Subject
Physics
Chapter
Center of Mass, Momentum and Collision

NEET · Physics · Center of Mass, Momentum and Collision

A body is moving uniformly in a straight line. If its kinetic...

A body is moving uniformly in a straight line. If its kinetic energy is 24 J24 \mathrm{~J} and its linear momentum is 12 kg m/s12 \mathrm{~kg} \mathrm{~m} / \mathrm{s}, the distance covered by the body in 5 s5 \mathrm{~s} is:

Options

  1. A10 m10 \mathrm{~m}
  2. B2.5 m2.5 \mathrm{~m}
  3. C20 m20 \mathrm{~m}
  4. D1440 m1440 \mathrm{~m}

Correct answer

C. 20 m20 \mathrm{~m}

Step-by-step solution

Given,
Kinetic energy, K=24 JK = 24 \mathrm{~J}
Linear momentum, p=12 kg m/sp = 12 \mathrm{~kg} \mathrm{~m} / \mathrm{s}
Time, t=5 st = 5 \mathrm{~s}

The relationship between kinetic energy and linear momentum is:
K=12pvK = \dfrac{1}{2} p v

Rearranging for velocity vv:
v=2Kpv = \dfrac{2K}{p}
v=2×2412=4 m/sv = \dfrac{2 \times 24}{12} = 4 \mathrm{~m/s}

The distance covered in 5 s5 \mathrm{~s} is:
d=v×td = v \times t
d=4×5=20 md = 4 \times 5 = 20 \mathrm{~m}

Answer: 20 m20 \mathrm{~m}
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