A particle of mass 250 ~g covers a distance of 120 ~m in 4 ~s while moving at a constant speed. The linear momentum of the particle is:

Correct answer: B. 7.5 ~kg ~m / s Given, m = 250 ~g = 0.25 ~kg d = 120 ~m t = 4 ~s The velocity of the particle is: v = (d)/(t) = (120)/(4) = 30 ~m/s The linear momentum p is given by: p = m × v p = 0.25 × 30 = 7.5 ~kg ~m / s Answer: 7.5 ~kg ~m / s

NEET

Exam: NEET
Subject: Physics
Chapter: Center of Mass, Momentum and Collision

NEET · Physics · Center of Mass, Momentum and Collision

A particle of mass 250 ~g covers a distance of 120 ~m in 4 ~s while...

A particle of mass

250 \mathrm{~g}

covers a distance of

120 \mathrm{~m}

4 \mathrm{~s}

while moving at a constant speed. The linear momentum of the particle is:

Options

A $75 \mathrm{~kg} \mathrm{~m} / \mathrm{s}$
B $7.5 \mathrm{~kg} \mathrm{~m} / \mathrm{s}$
C $30 \mathrm{~kg} \mathrm{~m} / \mathrm{s}$
D $7500 \mathrm{~kg} \mathrm{~m} / \mathrm{s}$

Correct answer

B. $7.5 \mathrm{~kg} \mathrm{~m} / \mathrm{s}$

Step-by-step solution

Given,

m = 250 \mathrm{~g} = 0.25 \mathrm{~kg}

d = 120 \mathrm{~m}

t = 4 \mathrm{~s}

The velocity of the particle is:

v = \dfrac{d}{t} = \dfrac{120}{4} = 30 \mathrm{~m/s}

The linear momentum

p

is given by:

p = m \times v

p = 0.25 \times 30 = 7.5 \mathrm{~kg} \mathrm{~m} / \mathrm{s}

Answer:

7.5 \mathrm{~kg} \mathrm{~m} / \mathrm{s}

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