A bulb is emitted electromagnetic radiation of 660 ~nm wavelength. The total energy of radiation is 3 × 10^ -18 ~J . The number of emitted photons will be (h=6.6 × 10^ -34 ~J ~s, c=3 × 10^8 ~m / s)

Correct answer: B. 10 Number of photons emitted =n aligned & E=(n h c)/(λ) & 3 × 10^ -18 = 6.6 × 10^ -34 × 3 × 10^8 × n 660 × 10^ -9 & n=(30)/(3)=10 aligned

AIIMS 201926 May

Exam: AIIMS
Year: 2019
Date: 26 May
Subject: Chemistry
Chapter: Structure of Atom

AIIMS 2019 · 26 May · Chemistry · Structure of Atom

A bulb is emitted electromagnetic radiation of 660 ~nm wavelength....

A bulb is emitted electromagnetic radiation of

660 \mathrm{~nm}

wavelength. The total energy of radiation is

3 \times 10^{-18} \mathrm{~J}

. The number of emitted photons will be

\left(h=6.6 \times 10^{-34} \mathrm{~J} \mathrm{~s}, c=3 \times 10^8 \mathrm{~m} / \mathrm{s}\right)

Options

A $1$
B $10$
C $100$
D $1000$

Correct answer

B. $10$

Step-by-step solution

Number of photons emitted

=n

\begin{aligned} & E=\frac{n h c}{\lambda} \\ & 3 \times 10^{-18}=\frac{6.6 \times 10^{-34} \times 3 \times 10^8 \times n}{660 \times 10^{-9}} \\ & n=\frac{30}{3}=10\end{aligned}

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