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AIIMS 201827 May
Exam
AIIMS
Year
2018
Date
27 May
Subject
Chemistry
Chapter
Structure of Atom

AIIMS 2018 · 27 May · Chemistry · Structure of Atom

Wavelength of a particular transition for H atom is 400 ~nm . What...

Wavelength of a particular transition for H\mathrm{H} atom is 400 nm400 \mathrm{~nm}. What can be the wavelength of He+\mathrm{He}^{+}for the same transition?Wavelength of a particular transition for H atom is 400 ~nm . What can be the wavelength of He^ + for the same

Options

  1. A400 nm400 \mathrm{~nm}
  2. B100 nm100 \mathrm{~nm}
  3. C1600 nm1600 \mathrm{~nm}
  4. D200 nm200 \mathrm{~nm}

Correct answer

B. 100 nm100 \mathrm{~nm}

Step-by-step solution

1λ=RH(1n12−1n22)×Z2\frac{1}{\lambda}=R_{\mathrm{H}}\left(\frac{1}{n_1^2}-\frac{1}{n_2^2}\right) \times Z^2 Wavelength of a particular transition for H atom is 400 ~nm . What can be the wavelength of He^ + for the same
On dividing equation (i) by (ii), we get λHe+=40022=4004=100 nm\lambda_{\mathrm{He}^{+}}=\frac{400}{2^2}=\frac{400}{4}=100 \mathrm{~nm}
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