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Exam
NEET
Subject
Physics
Chapter
Magnetic Effects of Current

NEET · Physics · Magnetic Effects of Current

Two long straight parallel wires are a distance d part. They carry...

Two long straight parallel wires are a distance dd part. They carry steady equal currents flowing out of the plane of the paper. The variation of magnetic field BB along the line xx′x x^{\prime} is given byTwo long straight parallel wires are a distance d part. They carry steady equal currents flowing out of the plane ofTwo long straight parallel wires are a distance d part. They carry steady equal currents flowing out of the plane ofTwo long straight parallel wires are a distance d part. They carry steady equal currents flowing out of the plane ofTwo long straight parallel wires are a distance d part. They carry steady equal currents flowing out of the plane of

Options

  1. AGiven below are two statements: one is labelled as Assertion (A) and the other is labelled as Reason (R). Assertion
  2. BGiven below are two statements: one is labelled as Assertion (A) and the other is labelled as Reason (R). Assertion
  3. CGiven below are two statements: one is labelled as Assertion (A) and the other is labelled as Reason (R). Assertion
  4. DGiven below are two statements: one is labelled as Assertion (A) and the other is labelled as Reason (R). Assertion

Correct answer

B. Given below are two statements: one is labelled as Assertion (A) and the other is labelled as Reason (R). Assertion

Step-by-step solution

The magnetic field in between because of each will be in opposite direction. Bin between =μ0i2πxj^−μ0i2π(2d−x)−j^=μ0i2π[1x−12d−x]j^B_{\text{in between }}=\frac{\mu_{0} i}{2 \pi x} \hat{\mathbf{j}}-\frac{\mu_{0} i}{2 \pi(2 d-x)}-\hat{\mathbf{j}} =\frac{\mu_{0} i}{2 \pi}\left[\frac{1}{x}-\frac{1}{2 d-x}\right] \hat{\mathbf{j}} At x=d,Bin between =0x=d, B_{\text{in between }}=0 For x<d,Bin between =j^x < d, B_{\text{in between }}=\hat{\mathbf{j}} For x>d,Bin between =−j^x>d, B_{\text{in between }}=-\hat{\mathbf{j}} Towards xx, net magnetic field will add up and direction will be (−j^)(-\hat{\mathbf{j}}). Towards x′x^{\prime}, net magnetic field will add up and direction will be (j^)(\hat{\mathbf{j}}).
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