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AIIMS 201826 May
Exam
AIIMS
Year
2018
Date
26 May
Subject
Chemistry
Chapter
Structure of Atom

AIIMS 2018 · 26 May · Chemistry · Structure of Atom

Calculate the velocity of an electron placed in the second orbit of...

Calculate the velocity of an electron placed in the second orbit of Li2+\mathrm{Li}^{2+} ion.

Options

  1. A0.521 m s−10.521 \mathrm{~m} \mathrm{~s}^{-1}
  2. B3.27×106 cm s−13.27 \times 10^6 \mathrm{~cm} \mathrm{~s}^{-1}
  3. C4.23×103 m s−14.23 \times 10^3 \mathrm{~m} \mathrm{~s}^{-1}
  4. D3.27×106 m s−13.27 \times 10^6 \mathrm{~m} \mathrm{~s}^{-1}

Correct answer

D. 3.27×106 m s−13.27 \times 10^6 \mathrm{~m} \mathrm{~s}^{-1}

Step-by-step solution

The velocity of an electron in nth n^{\text{th }} shell of the hydrogen like atom =2.18×106ms−1×Zn=\frac{2.18 \times 10^6 \mathrm{ ms}^{-1} \times Z}{n} On putting Z=3Z=3 and n=2n=2, v=2.18×106×32=3.27×106mv=\frac{2.18 \times 10^6 \times 3}{2}=3.27 \times 10^6 \mathrm{ m}s−1\mathrm{ s}^{-1}
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