A uniform circular ring of radius r is bent along its diameter such that the two semicircles lie in mutually perpendicular planes. A steady current I₀ enters the ring at one end of the common diameter and leaves at the other end. The magnitude of the net magnetic field at the center of the ring is:

Step-by-step solution

The uniform circular ring is bent along its diameter, forming two semicircles that share the same diameter but lie in mutually perpendicular planes. Since the current I₀ enters at one end of the common diameter and leaves at the other, it splits into two parallel paths corresponding to the two semicircles. Because the ring is uniform, the two semicircular paths have equal lengths and therefore equal resistances. The current divides equally between them: I₁ = I₂ = I₀ 2 The magnetic field at the center of a semicircl