A square loop A B C D , carrying a current I₂ , is placed near and coplanar with a long straight conductor X Y carrying a current I₁ , as shown in figure. The net force on the loop will be

Step-by-step solution

Force on arm A B due to current in conductor X Y is F₁= ₀ 4 2 I₁ I₂ L (L / 2) = ₀ I₁ I₂ acting towards the wire in the plane of loop. Force on arm C D due to current in conductor X Y is F₂= ₀ 4 2 I₁ I₂ L (3 L / 2) = ₀ I₁ I₂ 3 away from the wire the plane of loop. Net force on the loop =F₁-F₂= ₀ I₁ I₂ [1- 1 3 ]= 2 3 ₀ I₁ I₂