An electron moves at right angle to a magnetic field of 1.5 10⁻² ~T with a speed of 6 10^7 ~m / s . If the specific charge of the electron is 1.7 10¹¹ C / kg . The radius of the circular path will be

Step-by-step solution

The formula for radius of circular path is r= m v e B = v ( e m ) B ...(1) Given : e / m of electron aligned & =1.7 10¹¹ C / kg and v=6 10^7 ~m / s B & =1.5 10⁻² ~T aligned aligned So, r & = 6 10^7 1.7 10¹¹ 1.5 10⁻² & =2.35 10⁻² ~m =2.35 ~cm aligned