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Electric field associated with EM wave in free space is given by ( E =30 (6 10^8 t + kz ) i ) then match the following columns. ( array |l|l|l|l| & Column-I & & Column-II (a) & Direction of propagation of EM wave & (p) & -y axis (b) & Wave length of EM wave & (q) & 2 ~m ⁻¹ (c) & Direction of magnetic field of EM wave & (r) & 3.14 m (d) & Propagation constant 'k' of EM wave & (s) & '-z' axis array )

Options

  1. Aa-p, b-r, c-s, d-r
  2. Ba-s, b-r, c-p, d-q
  3. Ca-p, b-q, c-s, d-s
  4. Da-s, b-r, c-p, d-p

Correct answer

B. a-s, b-r, c-p, d-q

Step-by-step solution

The given electric field of the EM wave is: (E=30 (6 10^8 t+k z ) i ) Let's break it down: a) Direction of propagation: The term (k z ) in the equation indicates that the wave is propagating in the negative (z ) -axis (since the sign of (k z ) is positive in the sine function). Hence, the direction of propagation is along the -z axis. - b) Wavelength of the EM wave: The propagation constant (k ) is related to the wavelength by the formula (k= 2 ). From column-II, (k=2, ~m ⁻¹ ), so the wavelength ( = 2 2 = 3.14, ~m

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