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NEETPhysicsElectromagnetic Waves

The electric field of a plane electromagnetic wave propagating in vacuum has an amplitude of 30 2 V m ⁻¹ . The rms value of the oscillating magnetic field is: (Speed of light in vacuum = 3 10^8 m s ⁻¹ )

Options

  1. A2 10⁻⁷ T
  2. B5.0 10⁻⁸ T
  3. C1.0 10⁻⁷ T
  4. D9.0 10⁹ T

Correct answer

C. 1.0 10⁻⁷ T

Step-by-step solution

Given: Electric field amplitude, E₀ = 30 2 V m ⁻¹ Speed of light, c = 3 10^8 m s ⁻¹ First, find the amplitude (peak value) of the magnetic field using the relation c = E₀ B₀ : B₀ = E₀ c = 30 2 3 10^8 = 10 2 10⁻⁸ T = 2 10⁻⁷ T Next, calculate the rms value of the magnetic field using B_ rms = B₀ 2 : B_ rms = 2 10⁻⁷ 2 = 1.0 10⁻⁷ T Answer: 1.0 10⁻⁷ T

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