NEETPhysicsElectromagnetic Waves
The magnetic field of an electromagnetic wave travelling in a transparent medium is given by: B_y = 2 10⁻⁸ (10^3 z - 2 10¹¹ t ) T The corresponding expression for the electric field vector is:
Options
- AE_x = 4 (10^3 z - 2 10¹¹ t ) V/m
- BE_x = 6 (10^3 z - 2 10¹¹ t ) V/m
- CE_x = -4 (10^3 z - 2 10¹¹ t ) V/m
- DE_x = 10⁻¹⁶ (10^3 z - 2 10¹¹ t ) V/m
Correct answer
A. E_x = 4 (10^3 z - 2 10¹¹ t ) V/m
Step-by-step solution
From the given magnetic field equation, B_y = 2 10⁻⁸ (10^3 z - 2 10¹¹ t ) T , we can extract: Wave number, k = 10^3 rad/m Angular frequency, = 2 10¹¹ rad/s Magnetic field amplitude, B₀ = 2 10⁻⁸ T The speed of the wave in the medium is: v = k = 2 10¹¹ 10^3 = 2 10^8 m/s The amplitude of the electric field is: E₀ = v B₀ = (2 10^8) (2 10⁻⁸) = 4 V/m The phase argument (10^3 z - 2 10¹¹ t) indicates that the wave propagates in the +z direction ( v = k ). The magnetic field is in the +y direction ( B = j ). The direction o