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NEETPhysicsElectromagnetic Waves

Match List I with List II: List I (Wave Equation) List II (Direction of complementary field) (A) E = E₀ (kz - t) i (I) B is along k (B) B = B₀ ( t + ky) i (II) E is along - i (C) E = E₀ (kx - t) j (III) B is along j (D) B = B₀ (kz + t) j (IV) E is along - k Choose the correct answer from the options given below:

Options

  1. A(A)-(I), (B)-(II), (C)-(III), (D)-(IV)
  2. B(A)-(III), (B)-(II), (C)-(I), (D)-(IV)
  3. C(A)-(I), (B)-(IV), (C)-(III), (D)-(II)
  4. D(A)-(III), (B)-(IV), (C)-(I), (D)-(II)

Correct answer

D. (A)-(III), (B)-(IV), (C)-(I), (D)-(II)

Step-by-step solution

The direction of propagation of an electromagnetic wave is given by the direction of the cross product E B . (A) E is along i and the wave propagates along +z direction ( k ). E B = v i B = k . Since i j = k , B is along j (Matches III). (B) B is along i and the wave propagates along -y direction ( - j ). E B = v E i = - j . Since (- k ) i = - j , E is along - k (Matches IV). (C) E is along j and the wave propagates along +x direction ( i ). E B = v j B = i . Since j k = i , B is along k (Matches I). (D) B is along

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