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AIIMS 2015
Exam
AIIMS
Year
2015
Subject
Chemistry
Chapter
Structure of Atom

AIIMS 2015 · Chemistry · Structure of Atom

Which of the following arrangement is possible? array llll n & l &...

Which of the following arrangement is possible? nlms\begin{array}{llll}n & l & m & s\end{array}

Options

  1. A522+1/25 \quad 2 \quad 2 \quad+1 / 2
  2. B220−1/22 \quad 2 \quad 0 \quad-1 / 2
  3. C3−21+1/2\begin{array}{llll}3 & -2 & 1 & +1 / 2\end{array}
  4. D001+1/20 \quad 0 \quad 1 \quad+1 / 2

Correct answer

A. 522+1/25 \quad 2 \quad 2 \quad+1 / 2

Step-by-step solution

For a given value of n,l=0n, l=0 to n−1n-1; for a given value of l,m=−ll, m=-l to +l+l including zero; for a given value of m,s=+12,−12m, s=+\frac{1}{2},-\frac{1}{2} ∴\therefore \quad When n=5n=5, then l=0,1,2,3,4l=0,1,2,3,4; when l=2l=2, then m=−2,−1,0,+1,+2m=-2,-1,0,+1,+2 The value of ss can be ±1/2\pm 1 / 2 Hence, the arrangement, n=5,l=2,m=2n=5, l=2, m=2, s=+1/2s=+1 / 2 is possible for an electron.
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