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NEET
Exam
NEET
Subject
Physics
Chapter
Electromagnetic Waves

NEET · Physics · Electromagnetic Waves

Assertion (A): In a plane electromagnetic wave propagating in...

Assertion (A): In a plane electromagnetic wave propagating in vacuum, the ratio of the instantaneous magnitudes of the electric and magnetic fields (E/BE/B) is always constant and equal to cc.

Reason (R): In an electromagnetic wave, the electric and magnetic fields oscillate in phase and the ratio of their amplitudes is cc.

In the light of the above statements, choose the most appropriate answer from the options given below:

Options

  1. ABoth (A) and (R) are true and (R) is the correct explanation of (A)
  2. BBoth (A) and (R) are true but (R) is not the correct explanation of (A)
  3. C(A) is true but (R) is false
  4. D(A) is false but (R) is true

Correct answer

A. Both (A) and (R) are true and (R) is the correct explanation of (A)

Step-by-step solution

The instantaneous electric and magnetic fields in a plane electromagnetic wave are given by:

E=E0sin⁡(kx−ωt)E = E_0 \sin(kx - \omega t)
B=B0sin⁡(kx−ωt)B = B_0 \sin(kx - \omega t)

Since the fields oscillate in phase, the sine terms are identical. The ratio of their instantaneous magnitudes is:

EB=E0sin⁡(kx−ωt)B0sin⁡(kx−ωt)=E0B0\dfrac{E}{B} = \dfrac{E_0 \sin(kx - \omega t)}{B_0 \sin(kx - \omega t)} = \dfrac{E_0}{B_0}

Since the ratio of their amplitudes E0B0=c\dfrac{E_0}{B_0} = c, the instantaneous ratio EB\dfrac{E}{B} is also constant and equal to cc.

Thus, both (A) and (R) are true, and (R) is the correct explanation of (A).

Answer: Both (A) and (R) are true and (R) is the correct explanation of (A)
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