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NEETPhysicsElectromagnetic Waves

The spatial variation of the electric field of a plane electromagnetic wave travelling in vacuum at a given instant is described by a sinusoidal curve. The curve has a peak value of 60 V m ⁻¹ and a spatial period of 0.5 m . The amplitude of the oscillating magnetic field is: (Speed of light in vacuum = 3 10^8 m s ⁻¹ )

Options

  1. A1.8 10¹⁰ T
  2. B120 T
  3. C2.82 10⁻⁷ T
  4. D2.0 10⁻⁷ T

Correct answer

D. 2.0 10⁻⁷ T

Step-by-step solution

From the given description of the spatial variation, the peak value of the electric field is its amplitude, E₀ = 60 V m ⁻¹ . The spatial period (wavelength) is extra information and is not required to find the magnetic field amplitude. Using the relation between the amplitudes of the electric and magnetic fields in vacuum: B₀ = E₀ c B₀ = 60 3 10^8 = 20 10⁻⁸ T = 2.0 10⁻⁷ T Answer: 2.0 10⁻⁷ T

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