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Exam
NEET
Subject
Physics
Chapter
Wave Optics

NEET · Physics · Wave Optics

Given below are two statements : Statement I : If the Brewster's...

Given below are two statements :
Statement I : If the Brewster's angle for the light propagating from air to glass is θB{\theta}_{B}, then Brewster's angle for the light propagating from glass to air is π2−θB\dfrac{\pi}{2} - {\theta}_{B}.

Statement II : The Brewster's angle for the light propagating from glass to air is tan⁡−1(μg)\tan^{- 1}\left({\mu}_{g}\right), where μg{\mu}_{g} is the refractive index of glass.
In the light of the above statements, choose the correct answer from the options given below :

Given below are two statements : Statement I : If the Brewster's angle for the light propagating from air to glass is θ

Options

  1. ABoth Statements I and Statement II are true.
  2. BStatement I is true but Statement II is false.
  3. CBoth Statement I and Statement II are false.
  4. DStatement I is false but Statement II is true.

Correct answer

B. Statement I is true but Statement II is false.

Step-by-step solution

Given below are two statements : Statement I : If the Brewster's angle for the light propagating from air to glass is θ

Applying Snell's law, we get

μasini=μgsin⁡(90°−i){\mu}_{a}sini = {\mu}_{g}\sin \left(90 ° - i\right)

tani=μgμatani = \dfrac{{\mu}_{g}}{{\mu}_{a}}

When going from glass to air
tani′=μaμg=cotitan{i}^{'} = \dfrac{{\mu}_{a}}{{\mu}_{g}} = coti

Clearly, i′=(π2−i){i}^{'} = \left(\dfrac{\pi}{2} - i\right) & hence Statement I is true but Statement II is false.

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